Test over rotational motion moved to Thursday, 1/23. Be ready to start a new unit Wednesday 1/22.
Answers to Circular Motion Reinforcement
1a. 0.433 sec per rev
1b. 2.31 rev/s, 14.5 rad/s
1c. 13.05 m/s
1d. 2.84 N
1e. 0.0193 kg
2a. include T and Fg (no Fc in diagram)
2b. 1.15 sec per rev
2c. 0.87 rev/s, 5.46 rad/s
2d. 7.1 m/s
2e. 19.4 N
2f. 20.0 N at 76 degrees below vertical
3a. 0.75 rev/s, 4.7 rad/s
3b. 0.57 m/s
3c. should include Fn, Fg and Ff (no Fc - it's caused by Ff)
3d. 0.27
Answers to Example Problems
First problem.
1. 13.5 N
2. 12.0 N
3. 15.0 N
Second problem
coefficient of friction is 0.20 (Vt = 0.314 m/s)
1a. 0.433 sec per rev
1b. 2.31 rev/s, 14.5 rad/s
1c. 13.05 m/s
1d. 2.84 N
1e. 0.0193 kg
2a. include T and Fg (no Fc in diagram)
2b. 1.15 sec per rev
2c. 0.87 rev/s, 5.46 rad/s
2d. 7.1 m/s
2e. 19.4 N
2f. 20.0 N at 76 degrees below vertical
3a. 0.75 rev/s, 4.7 rad/s
3b. 0.57 m/s
3c. should include Fn, Fg and Ff (no Fc - it's caused by Ff)
3d. 0.27
Answers to Example Problems
First problem.
1. 13.5 N
2. 12.0 N
3. 15.0 N
Second problem
coefficient of friction is 0.20 (Vt = 0.314 m/s)